Folglich wegen (6), da h ′ = 0 {\displaystyle {\mathfrak {h}}'=0} {\displaystyle {\mathfrak {h}}'=0}:
(22) G x = k 2 l 4 w c 2 ∫ ( d ′ y 2 + d ′ z 2 ) d S = k l w c 2 ∫ ( d ′ y 2 + d ′ z 2 ) d S ′ . {\displaystyle {\mathfrak {G}}_{x}={\frac {k^{2}l^{4}w}{c^{2}}}\int \left({\mathfrak {d'}}_{y}^{2}+{\mathfrak {d'}}_{z}^{2}\right)dS={\frac {klw}{c^{2}}}\int \left({\mathfrak {d'}}_{y}^{2}+{\mathfrak {d'}}_{z}^{2}\right)dS'.} {\displaystyle {\mathfrak {G}}_{x}={\frac {k^{2}l^{4}w}{c^{2}}}\int \left({\mathfrak {d'}}_{y}^{2}+{\mathfrak {d'}}_{z}^{2}\right)dS={\frac {klw}{c^{2}}}\int \left({\mathfrak {d'}}_{y}^{2}+{\mathfrak {d'}}_{z}^{2}\right)dS'.}